9x^2-128=0

Solution for 9x^2-128=0 equation:

9x^2-128=0

a = 9; b = 0; c = -128;
Δ = b2-4ac
Δ = 02-4·9·(-128)
Δ = 4608
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{4608}=\sqrt{2304*2}=\sqrt{2304}*\sqrt{2}=48\sqrt{2}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-48\sqrt{2}}{2*9}=\frac{0-48\sqrt{2}}{18}
=-\frac{48\sqrt{2}}{18}
=-\frac{8\sqrt{2}}{3}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+48\sqrt{2}}{2*9}=\frac{0+48\sqrt{2}}{18}
=\frac{48\sqrt{2}}{18}
=\frac{8\sqrt{2}}{3}
$